Monopoly go square1/10/2024 ![]() ![]() 028 - this is partly explained by Chance re-directing the person landing to another square 7 out of 16 times. Perhaps most surprising is the Chance after free parking - way down at 0.0155 while its neighbours either side are at. But most frequent is square 24 (Trafalgar Sq- 0.031, however other red set members are less frequent than orange, reducing its value). The likelihood looks like: Orange set: about 0.0305 of all turns land on the 9th square (Vine st, most expensive of the set) with Marlborough st (its neighbour ) close behind (0.0295). The average frequency for all cells is 0.025 of course (1/40 squares) with the most common visited being Jail or visiting (every visit to square 30 forces a visit to Jail, doubling its frequency, plus the go to jail cards & rules). Start with the owner on Go (square 0 in the simulation) and toss the dice some 20000 times obeying the rules for each square you land on, it only takes a few seconds. How do we calculate the probability? A Markov Chain. ![]() The result is (as many of us supposed after empirical 'work') that you are most likely to arrive in the Orange set (Bow St, Vine St, Marlborough St when playing with a British set) and pay the rent to whoever owns it. But this is NOT so - every now and then you are sent to Jail (square 30 on the board, 2 cards = 1 in Community Chest one in Chance, and throw 3 doubles.) from which you start afresh, moving most likely 7 squares. Where are you most likely to end up? After a large number of throws you would expect - anywhere after all randomness will even out. The next throw you move on more spaces (again most likely 7) and so on.
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